(2x^2-3x)+(4x+4x^2)=0

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Solution for (2x^2-3x)+(4x+4x^2)=0 equation:


Simplifying
(2x2 + -3x) + (4x + 4x2) = 0

Reorder the terms:
(-3x + 2x2) + (4x + 4x2) = 0

Remove parenthesis around (-3x + 2x2)
-3x + 2x2 + (4x + 4x2) = 0

Remove parenthesis around (4x + 4x2)
-3x + 2x2 + 4x + 4x2 = 0

Reorder the terms:
-3x + 4x + 2x2 + 4x2 = 0

Combine like terms: -3x + 4x = 1x
1x + 2x2 + 4x2 = 0

Combine like terms: 2x2 + 4x2 = 6x2
1x + 6x2 = 0

Solving
1x + 6x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x'.
x(1 + 6x) = 0

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(1 + 6x)' equal to zero and attempt to solve: Simplifying 1 + 6x = 0 Solving 1 + 6x = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 6x = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 6x = 0 + -1 6x = 0 + -1 Combine like terms: 0 + -1 = -1 6x = -1 Divide each side by '6'. x = -0.1666666667 Simplifying x = -0.1666666667

Solution

x = {0, -0.1666666667}

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